Joules per kilogram kelvin to Calories per gram °C Converter

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Quick answer: To convert joules per kilogram kelvin to Calories per gram °C, multiply by 0.0002390057. For example, 10 J/(kg·K) is 0.002390057 cal/(g·°C). One joule per kilogram kelvin equals 0.0002390057 cal/(g·°C).

Use the Joules per kilogram kelvin to Calories per gram °C Converter

Joules per kilogram kelvin to Calories per gram °C formula and what each symbol means

cal/(g·°C) = J/(kg·K) × 0.0002390057

Symbols used in the formula
SymbolMeaning
J/(kg·K)Joule per kilogram kelvin
cal/(g·°C)Calorie per gram °C

Joules per kilogram kelvin to Calories per gram °C examples

1 J/(kg·K)

1 J/(kg·K) × 0.0002390057 = 0.0002390057 cal/(g·°C).

10 J/(kg·K)

10 J/(kg·K) × 0.0002390057 = 0.002390057 cal/(g·°C).

100 J/(kg·K)

100 J/(kg·K) × 0.0002390057 = 0.02390057 cal/(g·°C).

Joules per kilogram kelvin compared with Calories per gram °C

One cal/(g·°C) is 4,184 times as large as one J/(kg·K), so your number gets smaller when you convert joules per kilogram kelvin to Calories per gram °C and bigger when you convert back. If the answer is not smaller than what you typed, you multiplied instead of dividing.

About joules per kilogram kelvin and Calories per gram °C

Joule per kilogram kelvin (J/(kg·K)): The SI unit of specific heat capacity. Calorie per gram °C (cal/(g·°C)): Calories per gram per Celsius degree, 4,184 J/(kg·K) using the thermochemical calorie.

How to calculate Joules per kilogram kelvin to Calories per gram °C step by step

  1. Enter the value in J/(kg·K) (the starting unit).
  2. Multiply by 0.0002390057, because 1 J/(kg·K) = 0.0002390057 cal/(g·°C).
  3. The product is the value in cal/(g·°C). To go back, divide by 0.0002390057 or multiply by 4,184.

Popular specific heat capacity conversions

How to read your Joules per kilogram kelvin to Calories per gram °C result

Quick estimate: multiply by about 0.00024 to get Calories per gram °C from joules per kilogram kelvin; this is within 0.5% of the exact factor. Specific heat capacity is the energy needed to raise 1 kg of a substance by 1 K.

JOULES PER KILOGRAM KELVINCALORIES PER GRAM °C
10.0002390057
20.0004780115
50.001195029
100.002390057
200.004780115
500.01195029
1000.02390057
1,0000.2390057

Calories per gram °C to Joules per kilogram kelvin: quick table

CALORIES PER GRAM °CJOULES PER KILOGRAM KELVIN
14,184
520,920
1041,840
25104,600
50209,200
100418,400
2501,046,000
5002,092,000

Common mistakes when calculating Joules per kilogram kelvin to Calories per gram °C

  • Mixing the thermochemical calorie (4.184 J) with the International Table calorie (4.1868 J).
  • Dividing when you should multiply: from J/(kg·K) to cal/(g·°C) multiply by 0.0002390057; from cal/(g·°C) to J/(kg·K) divide by 0.0002390057.

Joules per kilogram kelvin to Calories per gram °C FAQ

How many cal/(g·°C) are in 1 J/(kg·K)?

1 J/(kg·K) equals 0.0002390057 cal/(g·°C).

How many J/(kg·K) are in 1 cal/(g·°C)?

1 cal/(g·°C) equals 4,184 J/(kg·K).

Is 1 J/(kg·K) = 0.0002390057 cal/(g·°C) an exact conversion?

The factor is shown rounded to 7 significant figures (0.0002390057). The calculator above uses more digits.

What is a calorie per gram °C (cal/(g·°C))?

Calories per gram per Celsius degree, 4,184 J/(kg·K) using the thermochemical calorie.

How can I estimate joules per kilogram kelvin to Calories per gram °C in my head?

Quick estimate: multiply by about 0.00024 to get Calories per gram °C from joules per kilogram kelvin; this is within 0.5% of the exact factor.

What is 500 J/(kg·K) in Calories per gram °C?

500 J/(kg·K) = 0.1195029 cal/(g·°C) (since 500 × 0.0002390057).

What is 15 J/(kg·K) in Calories per gram °C?

15 J/(kg·K) = 0.003585086 cal/(g·°C) (since 15 × 0.0002390057).

What is 75 J/(kg·K) in Calories per gram °C?

75 J/(kg·K) = 0.01792543 cal/(g·°C) (since 75 × 0.0002390057).

How many decimals should I keep when converting J/(kg·K) to cal/(g·°C)?

Match the precision of your original measurement. For example, 0.002390057 cal/(g·°C) rounds to 0.00239 cal/(g·°C) at 3 significant figures; keep more digits only for engineering or scientific work.

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Method, review and disclaimer

Edited by: Hemant Kumar and Anjita Rai, founders of ToolsVault (SEO and content professional, not a licensed adviser). Method: this tool runs in your browser using the formula shown on this page; the numbers you enter are not sent to our servers. Sources: NIST SP 811, Appendix B.8: conversion factors, BIPM: the International System of Units (SI)