Calories per gram °C to Joules per kilogram kelvin Converter
Quick answer: To convert Calories per gram °C to joules per kilogram kelvin, multiply by 4,184. For example, 10 cal/(g·°C) is 41,840 J/(kg·K). One calorie per gram °c equals 4,184 J/(kg·K).
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Use the Calories per gram °C to Joules per kilogram kelvin Converter
Calories per gram °C to Joules per kilogram kelvin formula and what each symbol means
J/(kg·K) = cal/(g·°C) × 4,184
| Symbol | Meaning |
|---|---|
| cal/(g·°C) | Calorie per gram °C |
| J/(kg·K) | Joule per kilogram kelvin |
Calories per gram °C to Joules per kilogram kelvin examples
1 cal/(g·°C)
1 cal/(g·°C) × 4,184 = 4,184 J/(kg·K).
10 cal/(g·°C)
10 cal/(g·°C) × 4,184 = 41,840 J/(kg·K).
100 cal/(g·°C)
100 cal/(g·°C) × 4,184 = 418,400 J/(kg·K).
Calories per gram °C compared with Joules per kilogram kelvin
One cal/(g·°C) is 4,184 times as large as one J/(kg·K), so your number gets bigger when you convert Calories per gram °C to joules per kilogram kelvin and smaller when you convert back. If the answer is not larger than what you typed, you divided instead of multiplying.
About Calories per gram °C and joules per kilogram kelvin
Calorie per gram °C (cal/(g·°C)): Calories per gram per Celsius degree, 4,184 J/(kg·K) using the thermochemical calorie. Joule per kilogram kelvin (J/(kg·K)): The SI unit of specific heat capacity.
How to calculate Calories per gram °C to Joules per kilogram kelvin step by step
- Enter the value in cal/(g·°C) (the starting unit).
- Multiply by 4,184, because 1 cal/(g·°C) = 4,184 J/(kg·K).
- The product is the value in J/(kg·K). To go back, divide by 4,184 or multiply by 0.0002390057.
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How to read your Calories per gram °C to Joules per kilogram kelvin result
Quick estimate: multiply by about 4,200 to get joules per kilogram kelvin from Calories per gram °C; this is within 0.4% of the exact factor. Specific heat capacity is the energy needed to raise 1 kg of a substance by 1 K.
| CALORIES PER GRAM °C | JOULES PER KILOGRAM KELVIN |
|---|---|
| 1 | 4,184 |
| 2 | 8,368 |
| 5 | 20,920 |
| 10 | 41,840 |
| 20 | 83,680 |
| 50 | 209,200 |
| 100 | 418,400 |
| 1,000 | 4,184,000 |
Joules per kilogram kelvin to Calories per gram °C: quick table
| JOULES PER KILOGRAM KELVIN | CALORIES PER GRAM °C |
|---|---|
| 1 | 0.0002390057 |
| 5 | 0.001195029 |
| 10 | 0.002390057 |
| 25 | 0.005975143 |
| 50 | 0.01195029 |
| 100 | 0.02390057 |
| 250 | 0.05975143 |
| 500 | 0.1195029 |
Common mistakes when calculating Calories per gram °C to Joules per kilogram kelvin
- Mixing the thermochemical calorie (4.184 J) with the International Table calorie (4.1868 J).
- Dividing when you should multiply: from cal/(g·°C) to J/(kg·K) multiply by 4,184; from J/(kg·K) to cal/(g·°C) divide by 4,184.
Calories per gram °C to Joules per kilogram kelvin FAQ
How many J/(kg·K) are in 1 cal/(g·°C)?
1 cal/(g·°C) equals 4,184 J/(kg·K).
How many cal/(g·°C) are in 1 J/(kg·K)?
1 J/(kg·K) equals 0.0002390057 cal/(g·°C).
Is 1 cal/(g·°C) = 4,184 J/(kg·K) an exact conversion?
The factor is shown rounded to 7 significant figures (4,184). The calculator above uses more digits.
What is a joule per kilogram kelvin (J/(kg·K))?
The SI unit of specific heat capacity.
How can I estimate Calories per gram °C to joules per kilogram kelvin in my head?
Quick estimate: multiply by about 4,200 to get joules per kilogram kelvin from Calories per gram °C; this is within 0.4% of the exact factor.
What is 25 cal/(g·°C) in joules per kilogram kelvin?
25 cal/(g·°C) = 104,600 J/(kg·K) (since 25 × 4,184).
What is 80 cal/(g·°C) in joules per kilogram kelvin?
80 cal/(g·°C) = 334,720 J/(kg·K) (since 80 × 4,184).
What is 500 cal/(g·°C) in joules per kilogram kelvin?
500 cal/(g·°C) = 2,092,000 J/(kg·K) (since 500 × 4,184).
How many decimals should I keep when converting cal/(g·°C) to J/(kg·K)?
Match the precision of your original measurement. For example, 41,840 J/(kg·K) rounds to 41,800 J/(kg·K) at 3 significant figures; keep more digits only for engineering or scientific work.
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Method, review and disclaimer
Edited by: Hemant Kumar and Anjita Rai, founders of ToolsVault (SEO and content professional, not a licensed adviser). Method: this tool runs in your browser using the formula shown on this page; the numbers you enter are not sent to our servers. Sources: NIST SP 811, Appendix B.8: conversion factors, BIPM: the International System of Units (SI)